# getting the axis position correctly

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dk on 20 Apr 2011
Edited: Yujendra Mitikiri on 23 Oct 2021
I can get the position of the axis easily
figure,plot([0 1], [0 1])
axis equal
AxesHandle=findobj(gcf,'Type','axes');
get(AxesHandle,'Position')
However when I modify the axis limits the axis position does not update.
axis tight
get(AxesHandle,'Position')
still gives me the same answer. How do I get the correct axis position in the second case?

Matt Fig on 20 Apr 2011
What changes is the tightinset property and plotboxaspectratio.
figure,plot([0 1], [0 1])
axis equal
AxesHandle=findobj(gcf,'Type','axes');
pt1 = get(AxesHandle,{'Position','tightinset','PlotBoxAspectRatio'});
pt1{:}
axis tight
pt2 = get(AxesHandle,{'Position','tightinset','PlotBoxAspectRatio'});
pt2{:}
Matt Fig on 20 Apr 2011
If you want to get the distance between the edge of the figure and the axis plot area, you need to stop using normalized units and switch to pixels. Then you will see a change.....
figure,plot([0 1], [0 1])
set(gcf,'position', [104 468 1831 420])
axis equal
axis tight
set(gca,'units','pix')
pt1 = get(gca,{'Position','tightinset'}); % [left bottom right top]
set(gca,'units','norm')
pt1{:}
set(gcf,'position', [104 468 793 420])
set(gca,'units','pix')
pt2 = get(gca,{'Position','tightinset'});
set(gca,'units','norm')
pt2{:}

Kelly Kearney on 20 Apr 2011
I wrote a little function that analyzes the aspect ratios and calculates the plotted axis region:
Should return exactly what you're looking for.
##### 2 CommentsShowHide 1 older comment
Yujendra Mitikiri on 23 Oct 2021
Thank you! This is exactly what I needed, in order to add annotations after making "axis equal."

Paulo Silva on 20 Apr 2011
The position remains the same, don't believe me? go to Tools and press Edit Plot, now click on the axis :)
One thing that do change is the:
xlim
dk on 20 Apr 2011
I know the matlab axis position property is not changing. What I want is the position of the actual plotting area.