How to delete k in random n set number?

Answer 1

[Steven Lord]

Use randperm to shuffle the numbers 1 through 20 and simply select the next element not yet chosen each time you need a random k.

[Muhammad Sam'an]

Thank you for answering ..

but I still find errors in my math code

here I am deaf in the mathlab code

clc;clear;close all;

c=[10 2 20 11

12 7 9 20

4 14 16 18];

s=[15

25

10

];

d=[5 15 15 15];

[m,n]=size(c);

x=zeros(m,n)

phi=1:m*n

while phi

k= randi(length(phi))

i=round(1+(k-1)/n)

j=[1+mod((k-1),n)]

x(i,j)=min(s(i),d(j))

s(i)= s(i)-x(i,j)

d(j)= d(j)-x(i,j)

end

I am also confused about which form of loop I should use between for or while .. because I still have problems, someone can provide a math code solution from Step 2.1 to Step 2.4, thanks

[Steven Lord]

randi generates numbers with replacement. randperm generates numbers without replacement.

rng default
x1 = randi(10, 1, 10)
x2 = randperm(10)

x1 contains the number 10 four times and doesn't contain 4, 5, or 8 at all.

x2 contains each number from 1 to 10 exactly once. You can iterate over the elements of that vector like so:

x2 = randperm(10);
for k = x2
    fprintf("Processing element %d.\n", k)
end

% or

M = zeros(10);
for ind = 1:10
    M(ind, x2(ind)) = ind;
end
disp(M)

[Muhammad Sam'an]

Thank you for the answer

clc;clear;close all;

c=[10 2 20 11

12 7 9 20

4 14 16 18];

s=[15

25

10

];

d=[5 15 15 15];

[m,n]=size(c);

x=zeros(m,n)

phi=1:m*n

while phi

k= randi(length(phi))

i=round(1+(k-1)/n)

j=[1+mod((k-1),n)]

x(i,j)=min(s(i),d(j))

s(i)= s(i)-x(i,j)

d(j)= d(j)-x(i,j)

end

want to ask again .. from my math lab code to repeat steps 2.1 to 2. 4 what do you use?

please help for the solution