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Dynamic variable names for MATLAB table

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Jay Vaidya
Jay Vaidya on 16 Nov 2020
Edited: Stephen on 16 Nov 2020
I am making the header names of the table as following:
colnames = [arrayfun(@(x) sprintf('type%d', x), 1:size(all_sorted), 'UniformOutput', false) arrayfun(@(x) sprintf('binary%d', x), 1:size(all_sorted), 'UniformOutput', false) 'result']
a_table = table(result_matrix, 'VariableNames',cell2mat(strcat({str2mat(colnames)})))
But always the last command gives error about
Error using table (line 259)
Invalid parameter name. Parameter name must be a nonempty string or character vector.
I tried a few permutations and combinations of converting the colnames to string, cell2mat, etc. But they give some or the other error. How can I specify the colnames with the above commands or with any of your other suggestions?
  1 Comment
Ameer Hamza
Ameer Hamza on 16 Nov 2020
The statement 1:size(all_sorted) can be confusing and may not mean what you think it means. Explicitly specifying the dimension will be helpful.

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Accepted Answer

Stephen
Stephen on 16 Nov 2020
Edited: Stephen on 16 Nov 2020
  • Use array2table instead of table (the wrong function, unless you really want the array in one variable).
  • Get rid of all of that cell2mat and strcat and str2mat confusion (what are you concatenating? Nothing).
all_sorted = [2;3;5];
result_matrix = randi(5,7)
result_matrix = 7×7
5 1 1 1 1 2 2 2 2 4 1 4 5 1 5 5 2 4 5 3 3 2 1 5 4 4 2 4 3 3 2 5 1 4 5 3 5 4 3 1 3 3 4 3 4 5 5 2 2
nr = size(all_sorted,1);
C1 = arrayfun(@(x) sprintf('type%d', x), 1:nr, 'UniformOutput', false)
C1 = 1x3 cell array
{'type1'} {'type2'} {'type3'}
C2 = arrayfun(@(x) sprintf('binary%d', x), 1:nr, 'UniformOutput', false)
C2 = 1x3 cell array
{'binary1'} {'binary2'} {'binary3'}
VN = [C1,C2,{'result'}];
T = array2table(result_matrix, 'VariableNames',VN)
T = 7x7 table
type1 type2 type3 binary1 binary2 binary3 result _____ _____ _____ _______ _______ _______ ______ 5 1 1 1 1 2 2 2 2 4 1 4 5 1 5 5 2 4 5 3 3 2 1 5 4 4 2 4 3 3 2 5 1 4 5 3 5 4 3 1 3 3 4 3 4 5 5 2 2

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