sort matrix by absolute value

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Poorva
Poorva on 29 Mar 2021
Commented: Poorva on 30 Mar 2021
How do I sort a matrix by absolute value and display its original value with +,- sign?

Accepted Answer

DGM
DGM on 29 Mar 2021
Edited: DGM on 29 Mar 2021
Consider the case for a vector:
A=randi(19,[10 1])-10
[~,idx]=sort(abs(A))
Asorted=A(idx)
For other arrays, you'll have to decide how exactly you want to sort it, and do the indexing accordingly.
  4 Comments
Poorva
Poorva on 30 Mar 2021
Thank you ....I got it now and the code is working well.
Poorva
Poorva on 30 Mar 2021
[y, idx2] = sort(D,2,'descend');
sx = size(C);
index = sub2ind(sx, repmat((1:sx(1)).', 1, sx(2)), idx2);
y2 = C(index);
res=array2table(y2)

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More Answers (1)

Steven Lord
Steven Lord on 30 Mar 2021
Specify the 'ComparisonMethod' name-value pair argument.
rng default
A = randi([-10 10], 5, 5)
A = 5×5
7 -8 -7 -8 3 9 -5 10 -2 -10 -8 1 10 9 7 9 10 0 6 9 3 10 6 10 4
[values, locations] = sort(A(:), 'ComparisonMethod', 'abs');
[values.'; locations.']
ans = 2×25
0 1 -2 3 3 4 -5 6 6 7 7 -7 -8 -8 -8 9 9 9 9 10 10 10 10 10 -10 14 8 17 5 21 25 7 15 19 1 23 11 3 6 16 2 4 18 24 9 10 12 13 20 22
  2 Comments
DGM
DGM on 30 Mar 2021
Do you know about when that option was introduced? I'm guessing it was some time around 2018, but release notes are vague and I only know it's not in R2015b.
Poorva
Poorva on 30 Mar 2021
thank you steven ....my code is working.

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