correction in order of elements in matrix obtained from reshape array

Hello everyone!

below is the code for calculation of C

A=[4 4 4; 8 8 8]
B=[16 12 8]
[mA,nA] = size(A);
[mB,nB] = size(B);
index=0;
for i=1:mA
  for j=1:nB
      index=index+1;
   c(index)=(min(A(i,j),B(1,j))/max(A(i,j),B(1,j)));
  end
end
C=[reshape(c,[],nB)]

I'm obtaining this matrix

C =  [0.2500   0.5000   0.6667
      0.3333   0.5000   1.0000]

but i want results as

C =  [0.2500   0.3333   0.5000
      0.5000   0.6667   1.0000]

[David Fletcher]

It's due to the way reshape fills the reshaped matrix from the elements of the original. To get it to do what you want you could reshape to a 3x2 matrix and then transpose

reshape(c,[],numel(c)/nB)'

ans =

0.2500 0.3333 0.5000

0.5000 0.6667 1.0000

[Karanvir singh Sohal]

Thanks @David Fletcher

This works fine. :)

Answer 1

[Matt J]

A loop-method,

A=[4 4 4; 8 8 8];

B=[16 12 8];

c=min(A,B(1,:))./max(A,B(1,:))

c = 2×3

0.2500 0.3333 0.5000 0.5000 0.6667 1.0000

[Karanvir singh Sohal]

This is great!!!!

No need of for loop.

I gonna check the efficiency of this solution for different size of the matrix before using. :)

Answer 2

[Matt J]

A=[4 4 4; 8 8 8]

A = 2×3

4 4 4 8 8 8

B=[16 12 8]

B = 1×3

16 12 8

[mA,nA] = size(A);
[mB,nB] = size(B);
index=0;
for j=1:nB
for i=1:mA
      index=index+1;
   c(index)=(min(A(i,j),B(1,j))/max(A(i,j),B(1,j)));
  end
end
C=reshape(c,[],nB)

C = 2×3

0.2500 0.3333 0.5000 0.5000 0.6667 1.0000

[Karanvir singh Sohal]

Thanks @Matt J

This is just a simple trick that works as my rquirement.

But using this as a solution maybe risky, if I forgot to switch the loops it may cause errors.