How do I delete slices in 3D-Array?

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Kay Schmidt on 8 Apr 2021
Edited: Stephen Cobeldick on 8 Apr 2021
Hey there,
I have a multidimensional Array where some of the slices along the third dimension only contains zeros in rows and columns. How do I delete those?
Thanks :)
Kay Schmidt on 8 Apr 2021
Thanks, works perfectly!

Matt J on 8 Apr 2021
Generating an example 3D array that has 10 slices
A = repmat([0 0 0 0; 1 0 0 0; 1 0 1 0],[1 1 10]);
Modifying the 4th & 8th slice to contain only zeros in rows and columns
A(:,:,4)=[0 0 0 0;0 0 0 0;0 0 0 0];
A(:,:,8)=[0 0 0 0;0 0 0 0;0 0 0 0]
A =
A(:,:,1) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,2) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,3) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,4) = 0 0 0 0 0 0 0 0 0 0 0 0 A(:,:,5) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,6) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,7) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,8) = 0 0 0 0 0 0 0 0 0 0 0 0 A(:,:,9) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,10) = 0 0 0 0 1 0 0 0 1 0 1 0
Find the slice index in 3rd dimension that has only zeros in rows and columns
idx = all(A == 0, [1 2]);
Now, delete the slices that has zeros from the original 3D array A
A(:,:,idx) = []
A =
A(:,:,1) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,2) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,3) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,4) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,5) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,6) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,7) = 0 0 0 0 1 0 0 0 1 0 1 0 A(:,:,8) = 0 0 0 0 1 0 0 0 1 0 1 0
I hope this gives you an idea how to solve your problem.

R2020b

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