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# problem in cell matrix operations

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Pooneh Shah Malekpoor on 14 May 2021
Answered: Walter Roberson on 14 May 2021
Hello
I have code like this which gives out a 5*1 cell matrix:
row = [0; 1; 2; 3; 4] ;
Coh = [15;16 ;17; 18; 20;19;7;8;22;25] ;
N = length(A) ;
Csurf = cell(N,1) ;
for i = 1:N
if row(i) == 0
Csurf{i} = 0 ;
else
Csurf{i} = Coh(1:row(i)) ;
Coh(1:row(i)) = [] ;
end
end
end
----------------------------------------------------
Now imagine that both row and Coh become cell matrices by the below repmat command,
Nmc=2
BB = repmat({row},Nmc,1);
CV=repmat({Coh},Nmc,1);
I have to write a code which considers the first cell of both BB and CV together and do the calculations as in the first code and then consider the second cell of BB and CV together and do the same calculations. The result would be a 5*2 cell matrix as Nmc=2. How should i formulate this?should i define a for loop? i am not good at cell indexing!
Any help is highly appreciated.
##### 1 CommentShowHide None
Adam Danz on 14 May 2021
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### Accepted Answer

Walter Roberson on 14 May 2021
Your current code would take 1 row from Coh, then the following 2 rows, then the following 3 rows, and so on. Is that what is desired?
If it is, then consider using mat2cell() . mat2cell() even handles counts of 0.
row = [0; 1; 2; 3; 4] ;
Coh = [15;16 ;17; 18; 20;19;7;8;22;25] ;
mat2cell(Coh, row, 1)
ans = 5×1 cell array
{0×1 double} {[ 15]} {2×1 double} {3×1 double} {4×1 double}
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