MATLAB Answers

Add context menu when LEFT click on button (app design)

23 views (last 30 days)
Veronica Taurino
Veronica Taurino on 21 Jun 2021
Edited: Johan C on 11 Aug 2021
Hi!
I am trying to add kind of a context menu after LEFT pushing a button on a specific tab of my app, but it seems not to be allowed. Suggestion for a workaround?
I tried uicontextmenu and this link hint (and here) but nothing happens when I push the botton:
function ButtonAddPlotPushed(app, event)
cm = uicontextmenu(app.UIFigure); %
m1 = uimenu(cm,'Text','Menu1');
m2 = uimenu(cm,'Text','Menu2');
m3 = uimenu(cm,'Text','Menu3');
pos = app.ButtonAddPlot.Position(1:2)
set(cm,'Position',pos);
set(cm,'Visible','on');
end
My GUI is something like this:
I need something like this:
I can't use a toolbar instead, because I need it just below the "Output Visualization" tab, while the toolbar is added on the top of the app:
  3 Comments
Veronica Taurino
Veronica Taurino on 28 Jun 2021
Is there a way to open the DROP DOWN menu by code? It would be enough to open it when clicking on the image as a callback, but I can't find a way

Sign in to comment.

Answers (2)

Vimal Rathod
Vimal Rathod on 23 Jun 2021
Hi,
You could try setting up 'HitTest' property of the Image to 'off' that way your UI could register its clicks and hopefully you could call the contextmenu.
Following link contains question similar to yours
  1 Comment
Veronica Taurino
Veronica Taurino on 28 Jun 2021
Thank you for your answer! How can I implement this solution in the app design? I am not able to find the HIT TEST property on the Inspector or elsewhere, I was looking for something like that. How do I set it?

Sign in to comment.


Johan C
Johan C on 11 Aug 2021
Edited: Johan C on 11 Aug 2021
This work for me, hope it helps.
properties (Access = private)
cm % Description
end
function startupFcn(app)
% Create ContextMenu
app.cm.ContextMenu = uicontextmenu(app.UIFigure);
% Create Menu1
app.cm.Menu1 = uimenu(app.cm.ContextMenu);
app.cm.Menu1.Text = 'menu1';
% Create Menu2
app.cm.Menu2 = uimenu(app.cm.ContextMenu);
app.cm.Menu2.Text = 'menu2';
end
function ButtonPushed(app, event)
open(app.cm.ContextMenu ,event.Source.Position([1 2]))
end
Best JC

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!