Help Fixing Leap Year Function

So i got a problem with my leap year calculator function which asks user to enter a year and function will tell you if its a leap year or not and ask you if you would like to repeator quit ,but i gota problem and dont really know how to fix it becuase am kinda of a noob.Any help would be great .

Getting erros like:

Line 3: END might be missing,possibly matching WHILE.

Line 9: Parse error at ELSE: usage might be invalid MATLAB syntax

function LeapYears 
condition = "yes";
while strcmp(condition,"yes") == 1
    year = input (' Enter the year : ');
    if mod(year,4) == 0     
        if mod(year,400) == 0 disp ('true')
        elseif mod(year,100) == 0 disp ('false')
        else disp ('true')   
        else disp ('false')            
    end
    condition = input("Would you like to repeat? (yes/no)\n", 's') == "yes";  
    end

[Sam Chak]

The original question may be beneficial to people who wish to learn how to test whether a given year is a leap year.

[Rena Berman]

(Answers Dev) Restored edit

Answer 1

[Jan]

Use the standard notation and no neat accumulation of commands per line:

function LeapYears 
condition = "yes";
while strcmp(condition, "yes")  % Optional:  == 1
    year = input (' Enter the year : ');
    if mod(year,4) == 0     
        if mod(year,400) == 0
            disp ('true')
        elseif mod(year,100) == 0
            disp ('false')
        else
            disp ('true')
        end   % <-- this was missing!
    else
       disp ('false')            
    end
    condition = input("Would you like to repeat? (yes/no)\n", 's');
    % The trailing == "yes"; is a bug.
    % You do not want [condition] to be TRUE or FALSE, but "yes".
end

A compact test:

if ~mod(year, 4) & (mod(year, 100) | ~mod(year, 400))
   disp('leap year')
else
   disp('no leap year')    
end

Answer 2

[Walter Roberson]

function LeapYears 
condition = "yes";
while strcmp(condition,"yes") == 1
    year = input (' Enter the year : ');
    if mod(year,4) == 0     
        if mod(year,400) == 0
            disp ('true')
        end
    elseif mod(year,100) == 0
        disp ('false')
    else

Okay, that else matches the elseif which is associated with the if mod(year,4) so it is fine.

        disp ('true')   
    else

But that else does not match anything. To use else, the previous control statement has to be if or elseif, not else

        disp ('false')            
    end
    condition = input("Would you like to repeat? (yes/no)\n", 's') == "yes";  
    end

I would also point put that if a year is NOT divisible by 4 (as needed to reach the elseif) then it cannot be divisible by 100.

        if mod(year,400) == 0
            disp ('true')
        end

Perhaps you wanted an else or elseif there?