Given a vector x, return a vector r that indicates the run length of any value in x. Each element in r shows how many times the corresponding element in x has appeared consecutively.
Example:
Input x = [5 3 3 1 0 9 9 4 4 4 4 5 1 2 2] Output r = [1 1 2 1 1 1 2 1 2 3 4 1 1 1 2]
The first test case seems to be invalid answer. Please check it
Hi Wenwu: Could you be more specific about what you think the problem is?
See FileExchange's seqle . (disclaimer: I'm the author)
False exemple description
y=[];
for i = 1:length(delta)
test = max(delta(1:i));
maxsofar=max(delta(1:i-1));
test2=min(delta(1:i));
minsofar=min(delta(1:i-1));
if test == delta(i) && delta(i)~= maxsofar
y=[y,1];
elseif test2 == delta(i) && delta(i)~= minsofar
y=[y,-1];
else
y=[y,0];
end
end
this code despite its giving correct results it is rejected by the tests...
the 1st test suite seems not right.
the sol of first test isn't correct
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