## Support Vector Machines for Binary Classification

### Understanding Support Vector Machines

#### Separable Data

You can use a support vector machine (SVM) when your data has exactly two classes. An SVM classifies data by finding the best hyperplane that separates all data points of one class from those of the other class. The *best* hyperplane for an SVM means the one with the largest *margin* between the two classes. Margin means the maximal width of the slab parallel to the hyperplane that has no interior data points.

The *support vectors* are the data points that are closest to the separating hyperplane; these points are on the boundary of the slab. The following figure illustrates these definitions, with + indicating data points of type 1, and – indicating data points of type –1.

**Mathematical Formulation: Primal. **This discussion follows Hastie, Tibshirani, and Friedman [1] and Christianini and Shawe-Taylor [2].

The data for training is a set of points (vectors) *x _{j}* along with their categories

*y*. For some dimension

_{j}*d*, the

*x*∊

_{j}*R*, and the

^{d}*y*= ±1. The equation of a hyperplane is

_{j}$$f(x)=x\prime \beta +b=0$$

where *β* ∊ *R ^{d}* and

*b*is a real number.

The following problem defines the *best* separating hyperplane (i.e., the decision boundary). Find *β* and *b* that minimize ||*β*|| such that for all data points (*x _{j}*,

*y*),

_{j}$${y}_{j}f\left({x}_{j}\right)\ge 1.$$

The support vectors are the *x _{j}* on the boundary, those for which $${y}_{j}f\left({x}_{j}\right)=1.$$

For mathematical convenience, the problem is usually given as the equivalent problem of minimizing $$\Vert \beta \Vert $$. This is a quadratic programming problem. The optimal solution $$\left(\widehat{\beta},\widehat{b}\right)$$ enables classification of a vector *z* as follows:

$$\text{class}(z)=\text{sign}\left(z\prime \widehat{\beta}+\widehat{b}\right)=\text{sign}\left(\widehat{f}\left(z\right)\right).$$

$$\widehat{f}\left(z\right)$$ is the *classification score* and represents the distance *z* is from the decision boundary.

**Mathematical Formulation: Dual. **It is computationally simpler to solve the dual quadratic programming problem. To obtain the dual, take positive Lagrange multipliers *α _{j}* multiplied by each constraint, and subtract from the objective function:

$${L}_{P}=\frac{1}{2}\beta \prime \beta -{\displaystyle \sum _{j}{\alpha}_{j}\left({y}_{j}\left({x}_{j}\prime \beta +b\right)-1\right)},$$

where you look for a stationary point of *L _{P}* over

*β*and

*b*. Setting the gradient of

*L*to 0, you get

_{P}$$\begin{array}{c}\beta ={\displaystyle \sum _{j}{\alpha}_{j}{y}_{j}{x}_{j}}\\ 0={\displaystyle \sum _{j}{\alpha}_{j}{y}_{j}}.\end{array}$$ | (1) |

Substituting into *L _{P}*, you get the dual

*L*:

_{D}$${L}_{D}={\displaystyle \sum _{j}{\alpha}_{j}}-\frac{1}{2}{\displaystyle \sum _{j}{\displaystyle \sum _{k}{\alpha}_{j}{\alpha}_{k}{y}_{j}{y}_{k}{x}_{j}\prime {x}_{k}}},$$

which you maximize over *α _{j}* ≥ 0. In general, many

*α*are 0 at the maximum. The nonzero

_{j}*α*in the solution to the dual problem define the hyperplane, as seen in Equation 1, which gives

_{j}*β*as the sum of

*α*. The data points

_{j}y_{j}x_{j}*x*corresponding to nonzero

_{j}*α*are the

_{j}*support vectors*.

The derivative of *L _{D}* with respect to a nonzero

*α*is 0 at an optimum. This gives

_{j}$${y}_{j}f\left({x}_{j}\right)-1=0.$$

In particular, this gives the value of *b* at the solution, by taking any *j* with nonzero *α _{j}*.

The dual is a standard quadratic programming problem. For example, the Optimization Toolbox™
`quadprog`

(Optimization Toolbox) solver solves this type of problem.

#### Nonseparable Data

Your data might not allow for a separating hyperplane. In that case, SVM can use a *soft margin*, meaning a hyperplane that separates many, but not all data points.

There are two standard formulations of soft margins. Both involve adding slack variables *ξ _{j}* and a penalty parameter

*C*.

The

*L*^{1}-norm problem is:$$\underset{\beta ,b,\xi}{\mathrm{min}}\left(\frac{1}{2}\beta \prime \beta +C{\displaystyle \sum _{j}{\xi}_{j}}\right)$$

such that

$$\begin{array}{c}{y}_{j}f\left({x}_{j}\right)\ge 1-{\xi}_{j}\\ {\xi}_{j}\ge 0.\end{array}$$

The

*L*^{1}-norm refers to using*ξ*as slack variables instead of their squares. The three solver options_{j}`SMO`

,`ISDA`

, and`L1QP`

of`fitcsvm`

minimize the*L*^{1}-norm problem.The

*L*^{2}-norm problem is:$$\underset{\beta ,b,\xi}{\mathrm{min}}\left(\frac{1}{2}\beta \prime \beta +C{\displaystyle \sum _{j}{\xi}_{j}^{2}}\right)$$

subject to the same constraints.

In these formulations, you can see that increasing *C* places more weight on the slack variables *ξ _{j}*, meaning the optimization attempts to make a stricter separation between classes. Equivalently, reducing

*C*towards 0 makes misclassification less important.

**Mathematical Formulation: Dual. **For easier calculations, consider the *L*^{1} dual problem to this soft-margin formulation. Using Lagrange multipliers *μ _{j}*, the function to minimize for the

*L*

^{1}-norm problem is:

$${L}_{P}=\frac{1}{2}\beta \prime \beta +C{\displaystyle \sum _{j}{\xi}_{j}}-{\displaystyle \sum _{j}{\alpha}_{j}\left({y}_{i}f\left({x}_{j}\right)-\left(1-{\xi}_{j}\right)\right)}-{\displaystyle \sum _{j}{\mu}_{j}{\xi}_{j}},$$

where you look for a stationary point of *L _{P}* over

*β*,

*b*, and positive

*ξ*. Setting the gradient of

_{j}*L*to 0, you get

_{P}$$\begin{array}{c}\beta ={\displaystyle \sum _{j}{\alpha}_{j}{y}_{j}{x}_{j}}\\ {\displaystyle \sum _{j}{\alpha}_{j}{y}_{j}}=0\\ {\alpha}_{j}=C-{\mu}_{j}\\ {\alpha}_{j},{\mu}_{j},{\xi}_{j}\ge 0.\end{array}$$

These equations lead directly to the dual formulation:

$$\underset{\alpha}{\mathrm{max}}{\displaystyle \sum _{j}{\alpha}_{j}}-\frac{1}{2}{\displaystyle \sum _{j}{\displaystyle \sum _{k}{\alpha}_{j}{\alpha}_{k}{y}_{j}{y}_{k}{x}_{j}\prime {x}_{k}}}$$

subject to the constraints

$$\begin{array}{l}{\displaystyle \sum _{j}{y}_{j}{\alpha}_{j}}=0\\ 0\le {\alpha}_{j}\le C.\end{array}$$

The final set of inequalities, 0 ≤ *α _{j}* ≤

*C*, shows why

*C*is sometimes called a

*box constraint*.

*C*keeps the allowable values of the Lagrange multipliers

*α*in a “box”, a bounded region.

_{j}The gradient equation for *b* gives the solution *b* in terms of the set of nonzero *α _{j}*, which correspond to the support vectors.

You can write and solve the dual of the *L*^{2}-norm problem in an analogous manner. For details, see Christianini and Shawe-Taylor [2], Chapter 6.

** fitcsvm Implementation. **Both dual soft-margin problems are quadratic programming problems. Internally,

`fitcsvm`

has several different algorithms for solving the problems.For one-class or binary classification, if you do not set a fraction of expected outliers in the data (see

`OutlierFraction`

), then the default solver is Sequential Minimal Optimization (SMO). SMO minimizes the one-norm problem by a series of two-point minimizations. During optimization, SMO respects the linear constraint $$\sum _{i}{\alpha}_{i}}{y}_{i}=0,$$ and explicitly includes the bias term in the model. SMO is relatively fast. For more details on SMO, see [3].For binary classification, if you set a fraction of expected outliers in the data, then the default solver is the Iterative Single Data Algorithm. Like SMO, ISDA solves the one-norm problem. Unlike SMO, ISDA minimizes by a series on one-point minimizations, does not respect the linear constraint, and does not explicitly include the bias term in the model. For more details on ISDA, see [4].

For one-class or binary classification, and if you have an Optimization Toolbox license, you can choose to use

`quadprog`

(Optimization Toolbox) to solve the one-norm problem.`quadprog`

uses a good deal of memory, but solves quadratic programs to a high degree of precision. For more details, see Quadratic Programming Definition (Optimization Toolbox).

#### Nonlinear Transformation with Kernels

Some binary classification problems do not have a simple hyperplane as a useful separating criterion. For those problems, there is a variant of the mathematical approach that retains nearly all the simplicity of an SVM separating hyperplane.

This approach uses these results from the theory of reproducing kernels:

There is a class of functions

*G*(*x*_{1},*x*_{2}) with the following property. There is a linear space*S*and a function*φ*mapping*x*to*S*such that*G*(*x*_{1},*x*_{2}) = <*φ*(*x*_{1}),*φ*(*x*_{2})>.The dot product takes place in the space

*S*.This class of functions includes:

Polynomials: For some positive integer

*p*,*G*(*x*_{1},*x*_{2}) = (1 +*x*_{1}′*x*_{2})^{p}.Radial basis function (Gaussian):

*G*(*x*_{1},*x*_{2}) = exp(–∥*x*_{1}–*x*_{2})∥^{2}).Multilayer perceptron or sigmoid (neural network): For a positive number

*p*_{1}and a negative number*p*_{2},*G*(*x*_{1},*x*_{2}) = tanh(*p*_{1}*x*_{1}′*x*_{2}+*p*_{2}).**Note**Not every set of

*p*_{1}and*p*_{2}yields a valid reproducing kernel.`fitcsvm`

does not support the sigmoid kernel. Instead, you can define the sigmoid kernel and specify it by using the`'KernelFunction'`

name-value pair argument. For details, see Train SVM Classifier Using Custom Kernel.

The mathematical approach using kernels relies on the computational method of hyperplanes. All the calculations for hyperplane classification use nothing more than dot products. Therefore, nonlinear kernels can use identical calculations and solution algorithms, and obtain classifiers that are nonlinear. The resulting classifiers are hypersurfaces in some space *S*, but the space *S* does not have to be identified or examined.

### Using Support Vector Machines

As with any supervised learning model, you first train a support vector machine, and then cross validate the classifier. Use the trained machine to classify (predict) new data. In addition, to obtain satisfactory predictive accuracy, you can use various SVM kernel functions, and you must tune the parameters of the kernel functions.

#### Training an SVM Classifier

Train, and optionally cross validate, an SVM classifier using `fitcsvm`

. The most common syntax is:

SVMModel = fitcsvm(X,Y,'KernelFunction','rbf',... 'Standardize',true,'ClassNames',{'negClass','posClass'});

The inputs are:

`X`

— Matrix of predictor data, where each row is one observation, and each column is one predictor.`Y`

— Array of class labels with each row corresponding to the value of the corresponding row in`X`

.`Y`

can be a categorical, character, or string array, a logical or numeric vector, or a cell array of character vectors.`KernelFunction`

— The default value is`'linear'`

for two-class learning, which separates the data by a hyperplane. The value`'gaussian'`

(or`'rbf'`

) is the default for one-class learning, and specifies to use the Gaussian (or radial basis function) kernel. An important step to successfully train an SVM classifier is to choose an appropriate kernel function.`Standardize`

— Flag indicating whether the software should standardize the predictors before training the classifier.`ClassNames`

— Distinguishes between the negative and positive classes, or specifies which classes to include in the data. The negative class is the first element (or row of a character array), e.g.,`'negClass'`

, and the positive class is the second element (or row of a character array), e.g.,`'posClass'`

.`ClassNames`

must be the same data type as`Y`

. It is good practice to specify the class names, especially if you are comparing the performance of different classifiers.

The resulting, trained model (`SVMModel`

) contains the optimized parameters from the SVM algorithm, enabling you to classify new data.

For more name-value pairs you can use to control the training, see the `fitcsvm`

reference page.

#### Classifying New Data with an SVM Classifier

Classify new data using `predict`

. The syntax for classifying new data using a trained SVM classifier (`SVMModel`

) is:

[label,score] = predict(SVMModel,newX);

The resulting vector, `label`

, represents the classification of each row in `X`

. `score`

is an *n*-by-2 matrix of soft scores. Each row corresponds to a row in `X`

, which is a new observation. The first column contains the scores for the observations being classified in the negative class, and the second column contains the scores observations being classified in the positive class.

To estimate posterior probabilities rather than scores, first pass the trained SVM classifier (`SVMModel`

) to `fitPosterior`

, which fits a score-to-posterior-probability transformation function to the scores. The syntax is:

ScoreSVMModel = fitPosterior(SVMModel,X,Y);

The property `ScoreTransform`

of the classifier `ScoreSVMModel`

contains the optimal transformation function. Pass `ScoreSVMModel`

to `predict`

. Rather than returning the scores, the output argument `score`

contains the posterior probabilities of an observation being classified in the negative (column 1 of `score`

) or positive (column 2 of `score`

) class.

#### Tuning an SVM Classifier

Use the `'OptimizeHyperparameters'`

name-value pair argument of `fitcsvm`

to find parameter values that minimize the cross-validation loss. The eligible parameters are `'BoxConstraint'`

, `'KernelFunction'`

, `'KernelScale'`

, `'PolynomialOrder'`

, and `'Standardize'`

. For an example, see Optimize Classifier Fit Using Bayesian Optimization. Alternatively, you can use the `bayesopt`

function, as shown in Optimize Cross-Validated Classifier Using bayesopt. The `bayesopt`

function allows more flexibility to customize optimization. You can use the `bayesopt`

function to optimize any parameters, including parameters that are not eligible to optimize when you use the `fitcsvm`

function.

You can also try tuning parameters of your classifier manually according to this scheme:

Pass the data to

`fitcsvm`

, and set the name-value pair argument`'KernelScale','auto'`

. Suppose that the trained SVM model is called`SVMModel`

. The software uses a heuristic procedure to select the kernel scale. The heuristic procedure uses subsampling. Therefore, to reproduce results, set a random number seed using`rng`

before training the classifier.Cross validate the classifier by passing it to

`crossval`

. By default, the software conducts 10-fold cross validation.Pass the cross-validated SVM model to

`kfoldLoss`

to estimate and retain the classification error.Retrain the SVM classifier, but adjust the

`'KernelScale'`

and`'BoxConstraint'`

name-value pair arguments.`BoxConstraint`

— One strategy is to try a geometric sequence of the box constraint parameter. For example, take 11 values, from`1e-5`

to`1e5`

by a factor of 10. Increasing`BoxConstraint`

might decrease the number of support vectors, but also might increase training time.`KernelScale`

— One strategy is to try a geometric sequence of the RBF sigma parameter scaled at the original kernel scale. Do this by:Retrieving the original kernel scale, e.g.,

`ks`

, using dot notation:`ks = SVMModel.KernelParameters.Scale`

.Use as new kernel scales factors of the original. For example, multiply

`ks`

by the 11 values`1e-5`

to`1e5`

, increasing by a factor of 10.

Choose the model that yields the lowest classification error. You might want to further refine your parameters to obtain better accuracy. Start with your initial parameters and perform another cross-validation step, this time using a factor of 1.2.

### Train SVM Classifiers Using a Gaussian Kernel

This example shows how to generate a nonlinear classifier with Gaussian kernel function. First, generate one class of points inside the unit disk in two dimensions, and another class of points in the annulus from radius 1 to radius 2. Then, generates a classifier based on the data with the Gaussian radial basis function kernel. The default linear classifier is obviously unsuitable for this problem, since the model is circularly symmetric. Set the box constraint parameter to `Inf`

to make a strict classification, meaning no misclassified training points. Other kernel functions might not work with this strict box constraint, since they might be unable to provide a strict classification. Even though the rbf classifier can separate the classes, the result can be overtrained.

Generate 100 points uniformly distributed in the unit disk. To do so, generate a radius *r* as the square root of a uniform random variable, generate an angle *t* uniformly in (0, $$2\pi $$), and put the point at (*r* cos(*t*), *r* sin(*t*)).

rng(1); % For reproducibility r = sqrt(rand(100,1)); % Radius t = 2*pi*rand(100,1); % Angle data1 = [r.*cos(t), r.*sin(t)]; % Points

Generate 100 points uniformly distributed in the annulus. The radius is again proportional to a square root, this time a square root of the uniform distribution from 1 through 4.

r2 = sqrt(3*rand(100,1)+1); % Radius t2 = 2*pi*rand(100,1); % Angle data2 = [r2.*cos(t2), r2.*sin(t2)]; % points

Plot the points, and plot circles of radii 1 and 2 for comparison.

figure; plot(data1(:,1),data1(:,2),'r.','MarkerSize',15) hold on plot(data2(:,1),data2(:,2),'b.','MarkerSize',15) ezpolar(@(x)1);ezpolar(@(x)2); axis equal hold off

Put the data in one matrix, and make a vector of classifications.

data3 = [data1;data2]; theclass = ones(200,1); theclass(1:100) = -1;

Train an SVM classifier with `KernelFunction`

set to `'rbf'`

and `BoxConstraint`

set to `Inf`

. Plot the decision boundary and flag the support vectors.

%Train the SVM Classifier cl = fitcsvm(data3,theclass,'KernelFunction','rbf',... 'BoxConstraint',Inf,'ClassNames',[-1,1]); % Predict scores over the grid d = 0.02; [x1Grid,x2Grid] = meshgrid(min(data3(:,1)):d:max(data3(:,1)),... min(data3(:,2)):d:max(data3(:,2))); xGrid = [x1Grid(:),x2Grid(:)]; [~,scores] = predict(cl,xGrid); % Plot the data and the decision boundary figure; h(1:2) = gscatter(data3(:,1),data3(:,2),theclass,'rb','.'); hold on ezpolar(@(x)1); h(3) = plot(data3(cl.IsSupportVector,1),data3(cl.IsSupportVector,2),'ko'); contour(x1Grid,x2Grid,reshape(scores(:,2),size(x1Grid)),[0 0],'k'); legend(h,{'-1','+1','Support Vectors'}); axis equal hold off

`fitcsvm`

generates a classifier that is close to a circle of radius 1. The difference is due to the random training data.

Training with the default parameters makes a more nearly circular classification boundary, but one that misclassifies some training data. Also, the default value of `BoxConstraint`

is `1`

, and, therefore, there are more support vectors.

cl2 = fitcsvm(data3,theclass,'KernelFunction','rbf'); [~,scores2] = predict(cl2,xGrid); figure; h(1:2) = gscatter(data3(:,1),data3(:,2),theclass,'rb','.'); hold on ezpolar(@(x)1); h(3) = plot(data3(cl2.IsSupportVector,1),data3(cl2.IsSupportVector,2),'ko'); contour(x1Grid,x2Grid,reshape(scores2(:,2),size(x1Grid)),[0 0],'k'); legend(h,{'-1','+1','Support Vectors'}); axis equal hold off

### Train SVM Classifier Using Custom Kernel

This example shows how to use a custom kernel function, such as the sigmoid kernel, to train SVM classifiers, and adjust custom kernel function parameters.

Generate a random set of points within the unit circle. Label points in the first and third quadrants as belonging to the positive class, and those in the second and fourth quadrants in the negative class.

rng(1); % For reproducibility n = 100; % Number of points per quadrant r1 = sqrt(rand(2*n,1)); % Random radii t1 = [pi/2*rand(n,1); (pi/2*rand(n,1)+pi)]; % Random angles for Q1 and Q3 X1 = [r1.*cos(t1) r1.*sin(t1)]; % Polar-to-Cartesian conversion r2 = sqrt(rand(2*n,1)); t2 = [pi/2*rand(n,1)+pi/2; (pi/2*rand(n,1)-pi/2)]; % Random angles for Q2 and Q4 X2 = [r2.*cos(t2) r2.*sin(t2)]; X = [X1; X2]; % Predictors Y = ones(4*n,1); Y(2*n + 1:end) = -1; % Labels

Plot the data.

```
figure;
gscatter(X(:,1),X(:,2),Y);
title('Scatter Diagram of Simulated Data')
```

Write a function that accepts two matrices in the feature space as inputs, and transforms them into a Gram matrix using the sigmoid kernel.

function G = mysigmoid(U,V) % Sigmoid kernel function with slope gamma and intercept c gamma = 1; c = -1; G = tanh(gamma*U*V' + c); end

Save this code as a file named `mysigmoid`

on your MATLAB® path.

Train an SVM classifier using the sigmoid kernel function. It is good practice to standardize the data.

Mdl1 = fitcsvm(X,Y,'KernelFunction','mysigmoid','Standardize',true);

`Mdl1`

is a `ClassificationSVM`

classifier containing the estimated parameters.

Plot the data, and identify the support vectors and the decision boundary.

% Compute the scores over a grid d = 0.02; % Step size of the grid [x1Grid,x2Grid] = meshgrid(min(X(:,1)):d:max(X(:,1)),... min(X(:,2)):d:max(X(:,2))); xGrid = [x1Grid(:),x2Grid(:)]; % The grid [~,scores1] = predict(Mdl1,xGrid); % The scores figure; h(1:2) = gscatter(X(:,1),X(:,2),Y); hold on h(3) = plot(X(Mdl1.IsSupportVector,1),... X(Mdl1.IsSupportVector,2),'ko','MarkerSize',10); % Support vectors contour(x1Grid,x2Grid,reshape(scores1(:,2),size(x1Grid)),[0 0],'k'); % Decision boundary title('Scatter Diagram with the Decision Boundary') legend({'-1','1','Support Vectors'},'Location','Best'); hold off

You can adjust the kernel parameters in an attempt to improve the shape of the decision boundary. This might also decrease the within-sample misclassification rate, but, you should first determine the out-of-sample misclassification rate.

Determine the out-of-sample misclassification rate by using 10-fold cross validation.

CVMdl1 = crossval(Mdl1); misclass1 = kfoldLoss(CVMdl1); misclass1

misclass1 = 0.1350

The out-of-sample misclassification rate is 13.5%.

Write another sigmoid function, but Set `gamma = 0.5;`

.

function G = mysigmoid2(U,V) % Sigmoid kernel function with slope gamma and intercept c gamma = 0.5; c = -1; G = tanh(gamma*U*V' + c); end

Save this code as a file named `mysigmoid2`

on your MATLAB® path.

Train another SVM classifier using the adjusted sigmoid kernel. Plot the data and the decision region, and determine the out-of-sample misclassification rate.

Mdl2 = fitcsvm(X,Y,'KernelFunction','mysigmoid2','Standardize',true); [~,scores2] = predict(Mdl2,xGrid); figure; h(1:2) = gscatter(X(:,1),X(:,2),Y); hold on h(3) = plot(X(Mdl2.IsSupportVector,1),... X(Mdl2.IsSupportVector,2),'ko','MarkerSize',10); title('Scatter Diagram with the Decision Boundary') contour(x1Grid,x2Grid,reshape(scores2(:,2),size(x1Grid)),[0 0],'k'); legend({'-1','1','Support Vectors'},'Location','Best'); hold off CVMdl2 = crossval(Mdl2); misclass2 = kfoldLoss(CVMdl2); misclass2

misclass2 = 0.0450

After the sigmoid slope adjustment, the new decision boundary seems to provide a better within-sample fit, and the cross-validation rate contracts by more than 66%.

### Optimize Classifier Fit Using Bayesian Optimization

This example shows how to optimize an SVM classification using the `fitcsvm`

function and the `OptimizeHyperparameters`

name-value argument.

**Generate Data**

The classification works on locations of points from a Gaussian mixture model. In *The Elements of Statistical Learning*, Hastie, Tibshirani, and Friedman (2009), page 17 describes the model. The model begins with generating 10 base points for a "green" class, distributed as 2-D independent normals with mean (1,0) and unit variance. It also generates 10 base points for a "red" class, distributed as 2-D independent normals with mean (0,1) and unit variance. For each class (green and red), generate 100 random points as follows:

Choose a base point

*m*of the appropriate color uniformly at random.Generate an independent random point with 2-D normal distribution with mean

*m*and variance I/5, where I is the 2-by-2 identity matrix. In this example, use a variance I/50 to show the advantage of optimization more clearly.

Generate the 10 base points for each class.

rng('default') % For reproducibility grnpop = mvnrnd([1,0],eye(2),10); redpop = mvnrnd([0,1],eye(2),10);

View the base points.

plot(grnpop(:,1),grnpop(:,2),'go') hold on plot(redpop(:,1),redpop(:,2),'ro') hold off

Since some red base points are close to green base points, it can be difficult to classify the data points based on location alone.

Generate the 100 data points of each class.

redpts = zeros(100,2); grnpts = redpts; for i = 1:100 grnpts(i,:) = mvnrnd(grnpop(randi(10),:),eye(2)*0.02); redpts(i,:) = mvnrnd(redpop(randi(10),:),eye(2)*0.02); end

View the data points.

figure plot(grnpts(:,1),grnpts(:,2),'go') hold on plot(redpts(:,1),redpts(:,2),'ro') hold off

**Prepare Data for Classification**

Put the data into one matrix, and make a vector `grp`

that labels the class of each point. 1 indicates the green class, and –1 indicates the red class.

cdata = [grnpts;redpts]; grp = ones(200,1); grp(101:200) = -1;

**Prepare Cross-Validation**

Set up a partition for cross-validation.

`c = cvpartition(200,'KFold',10);`

This step is optional. If you specify a partition for the optimization, then you can compute an actual cross-validation loss for the returned model.

**Optimize Fit**

To find a good fit, meaning one with optimal hyperparameters that minimize the cross-validation loss, use Bayesian optimization. Specify a list of hyperparameters to optimize by using the `OptimizeHyperparameters`

name-value argument, and specify optimization options by using the `HyperparameterOptimizationOptions`

name-value argument.

Specify `'OptimizeHyperparameters'`

as `'auto'`

. The `'auto'`

option includes a typical set of hyperparameters to optimize. `fitcsvm`

finds optimal values of `BoxConstraint`

and `KernelScale`

. Set the hyperparameter optimization options to use the cross-validation partition `c`

and to choose the `'expected-improvement-plus'`

acquisition function for reproducibility. The default acquisition function depends on run time and, therefore, can give varying results.

opts = struct('CVPartition',c,'AcquisitionFunctionName','expected-improvement-plus'); Mdl = fitcsvm(cdata,grp,'KernelFunction','rbf', ... 'OptimizeHyperparameters','auto','HyperparameterOptimizationOptions',opts)

|=====================================================================================================| | Iter | Eval | Objective | Objective | BestSoFar | BestSoFar | BoxConstraint| KernelScale | | | result | | runtime | (observed) | (estim.) | | | |=====================================================================================================| | 1 | Best | 0.345 | 0.29267 | 0.345 | 0.345 | 0.00474 | 306.44 | | 2 | Best | 0.115 | 0.2533 | 0.115 | 0.12678 | 430.31 | 1.4864 | | 3 | Accept | 0.52 | 0.34453 | 0.115 | 0.1152 | 0.028415 | 0.014369 | | 4 | Accept | 0.61 | 0.54853 | 0.115 | 0.11504 | 133.94 | 0.0031427 | | 5 | Accept | 0.34 | 0.65994 | 0.115 | 0.11504 | 0.010993 | 5.7742 | | 6 | Best | 0.085 | 0.38782 | 0.085 | 0.085039 | 885.63 | 0.68403 | | 7 | Accept | 0.105 | 0.33833 | 0.085 | 0.085428 | 0.3057 | 0.58118 | | 8 | Accept | 0.21 | 0.3605 | 0.085 | 0.09566 | 0.16044 | 0.91824 | | 9 | Accept | 0.085 | 0.43178 | 0.085 | 0.08725 | 972.19 | 0.46259 | | 10 | Accept | 0.1 | 0.55425 | 0.085 | 0.090952 | 990.29 | 0.491 | | 11 | Best | 0.08 | 0.35106 | 0.08 | 0.079362 | 2.5195 | 0.291 | | 12 | Accept | 0.09 | 0.28641 | 0.08 | 0.08402 | 14.338 | 0.44386 | | 13 | Accept | 0.1 | 0.36434 | 0.08 | 0.08508 | 0.0022577 | 0.23803 | | 14 | Accept | 0.11 | 0.20452 | 0.08 | 0.087378 | 0.2115 | 0.32109 | | 15 | Best | 0.07 | 0.21267 | 0.07 | 0.081507 | 910.2 | 0.25218 | | 16 | Best | 0.065 | 0.29162 | 0.065 | 0.072457 | 953.22 | 0.26253 | | 17 | Accept | 0.075 | 0.35551 | 0.065 | 0.072554 | 998.74 | 0.23087 | | 18 | Accept | 0.295 | 0.35477 | 0.065 | 0.072647 | 996.18 | 44.626 | | 19 | Accept | 0.07 | 0.31313 | 0.065 | 0.06946 | 985.37 | 0.27389 | | 20 | Accept | 0.165 | 0.25283 | 0.065 | 0.071622 | 0.065103 | 0.13679 | |=====================================================================================================| | Iter | Eval | Objective | Objective | BestSoFar | BestSoFar | BoxConstraint| KernelScale | | | result | | runtime | (observed) | (estim.) | | | |=====================================================================================================| | 21 | Accept | 0.345 | 0.27125 | 0.065 | 0.071764 | 971.7 | 999.01 | | 22 | Accept | 0.61 | 0.30689 | 0.065 | 0.071967 | 0.0010168 | 0.0010005 | | 23 | Accept | 0.345 | 0.32293 | 0.065 | 0.071959 | 0.0011459 | 995.89 | | 24 | Accept | 0.35 | 0.28572 | 0.065 | 0.071863 | 0.0010003 | 40.628 | | 25 | Accept | 0.24 | 0.41658 | 0.065 | 0.072124 | 996.55 | 10.423 | | 26 | Accept | 0.61 | 0.85097 | 0.065 | 0.072067 | 994.71 | 0.0010063 | | 27 | Accept | 0.47 | 0.25675 | 0.065 | 0.07218 | 993.69 | 0.029723 | | 28 | Accept | 0.3 | 0.443 | 0.065 | 0.072291 | 993.15 | 170.01 | | 29 | Accept | 0.16 | 0.39018 | 0.065 | 0.072103 | 992.81 | 3.8594 | | 30 | Accept | 0.365 | 0.29585 | 0.065 | 0.072112 | 0.0010017 | 0.044287 |

__________________________________________________________ Optimization completed. MaxObjectiveEvaluations of 30 reached. Total function evaluations: 30 Total elapsed time: 54.1661 seconds Total objective function evaluation time: 10.9986 Best observed feasible point: BoxConstraint KernelScale _____________ ___________ 953.22 0.26253 Observed objective function value = 0.065 Estimated objective function value = 0.073726 Function evaluation time = 0.29162 Best estimated feasible point (according to models): BoxConstraint KernelScale _____________ ___________ 985.37 0.27389 Estimated objective function value = 0.072112 Estimated function evaluation time = 0.32078

Mdl = ClassificationSVM ResponseName: 'Y' CategoricalPredictors: [] ClassNames: [-1 1] ScoreTransform: 'none' NumObservations: 200 HyperparameterOptimizationResults: [1x1 BayesianOptimization] Alpha: [77x1 double] Bias: -0.2352 KernelParameters: [1x1 struct] BoxConstraints: [200x1 double] ConvergenceInfo: [1x1 struct] IsSupportVector: [200x1 logical] Solver: 'SMO' Properties, Methods

`fitcsvm`

returns a `ClassificationSVM`

model object that uses the best estimated feasible point. The best estimated feasible point is the set of hyperparameters that minimizes the upper confidence bound of the cross-validation loss based on the underlying Gaussian process model of the Bayesian optimization process.

The Bayesian optimization process internally maintains a Gaussian process model of the objective function. The objective function is the cross-validated misclassification rate for classification. For each iteration, the optimization process updates the Gaussian process model and uses the model to find a new set of hyperparameters. Each line of the iterative display shows the new set of hyperparameters and these column values:

`Objective`

— Objective function value computed at the new set of hyperparameters.`Objective runtime`

— Objective function evaluation time.`Eval result`

— Result report, specified as`Accept`

,`Best`

, or`Error`

.`Accept`

indicates that the objective function returns a finite value, and`Error`

indicates that the objective function returns a value that is not a finite real scalar.`Best`

indicates that the objective function returns a finite value that is lower than previously computed objective function values.`BestSoFar(observed)`

— The minimum objective function value computed so far. This value is either the objective function value of the current iteration (if the`Eval result`

value for the current iteration is`Best`

) or the value of the previous`Best`

iteration.`BestSoFar(estim.)`

— At each iteration, the software estimates the upper confidence bounds of the objective function values, using the updated Gaussian process model, at all the sets of hyperparameters tried so far. Then the software chooses the point with the minimum upper confidence bound. The`BestSoFar(estim.)`

value is the objective function value returned by the`predictObjective`

function at the minimum point.

The plot below the iterative display shows the `BestSoFar(observed)`

and `BestSoFar(estim.)`

values in blue and green, respectively.

The returned object `Mdl`

uses the best estimated feasible point, that is, the set of hyperparameters that produces the `BestSoFar(estim.)`

value in the final iteration based on the final Gaussian process model.

You can obtain the best point from the `HyperparameterOptimizationResults`

property or by using the `bestPoint`

function.

Mdl.HyperparameterOptimizationResults.XAtMinEstimatedObjective

`ans=`*1×2 table*
BoxConstraint KernelScale
_____________ ___________
985.37 0.27389

[x,CriterionValue,iteration] = bestPoint(Mdl.HyperparameterOptimizationResults)

`x=`*1×2 table*
BoxConstraint KernelScale
_____________ ___________
985.37 0.27389

CriterionValue = 0.0888

iteration = 19

By default, the `bestPoint`

function uses the `'min-visited-upper-confidence-interval'`

criterion. This criterion chooses the hyperparameters obtained from the 19th iteration as the best point. `CriterionValue`

is the upper bound of the cross-validated loss computed by the final Gaussian process model. Compute the actual cross-validated loss by using the partition `c`

.

L_MinEstimated = kfoldLoss(fitcsvm(cdata,grp,'CVPartition',c,'KernelFunction','rbf', ... 'BoxConstraint',x.BoxConstraint,'KernelScale',x.KernelScale))

L_MinEstimated = 0.0700

The actual cross-validated loss is close to the estimated value. The `Estimated objective function value`

is displayed below the plots of the optimization results.

You can also extract the best observed feasible point (that is, the last `Best`

point in the iterative display) from the `HyperparameterOptimizationResults`

property or by specifying `Criterion`

as `'min-observed'`

.

Mdl.HyperparameterOptimizationResults.XAtMinObjective

`ans=`*1×2 table*
BoxConstraint KernelScale
_____________ ___________
953.22 0.26253

[x_observed,CriterionValue_observed,iteration_observed] = bestPoint(Mdl.HyperparameterOptimizationResults,'Criterion','min-observed')

`x_observed=`*1×2 table*
BoxConstraint KernelScale
_____________ ___________
953.22 0.26253

CriterionValue_observed = 0.0650

iteration_observed = 16

The `'min-observed'`

criterion chooses the hyperparameters obtained from the 16th iteration as the best point. `CriterionValue_observed`

is the actual cross-validated loss computed using the selected hyperparameters. For more information, see the Criterion name-value argument of `bestPoint`

.

Visualize the optimized classifier.

d = 0.02; [x1Grid,x2Grid] = meshgrid(min(cdata(:,1)):d:max(cdata(:,1)), ... min(cdata(:,2)):d:max(cdata(:,2))); xGrid = [x1Grid(:),x2Grid(:)]; [~,scores] = predict(Mdl,xGrid); figure h(1:2) = gscatter(cdata(:,1),cdata(:,2),grp,'rg','+*'); hold on h(3) = plot(cdata(Mdl.IsSupportVector,1), ... cdata(Mdl.IsSupportVector,2),'ko'); contour(x1Grid,x2Grid,reshape(scores(:,2),size(x1Grid)),[0 0],'k'); legend(h,{'-1','+1','Support Vectors'},'Location','Southeast');

**Evaluate Accuracy on New Data**

Generate and classify new test data points.

grnobj = gmdistribution(grnpop,.2*eye(2)); redobj = gmdistribution(redpop,.2*eye(2)); newData = random(grnobj,10); newData = [newData;random(redobj,10)]; grpData = ones(20,1); % green = 1 grpData(11:20) = -1; % red = -1 v = predict(Mdl,newData);

Compute the misclassification rates on the test data set.

L_Test = loss(Mdl,newData,grpData)

L_Test = 0.3500

Determine which new data points are classified correctly. Format the correctly classified points in red squares and the incorrectly classified points in black squares.

h(4:5) = gscatter(newData(:,1),newData(:,2),v,'mc','**'); mydiff = (v == grpData); % Classified correctly for ii = mydiff % Plot red squares around correct pts h(6) = plot(newData(ii,1),newData(ii,2),'rs','MarkerSize',12); end for ii = not(mydiff) % Plot black squares around incorrect pts h(7) = plot(newData(ii,1),newData(ii,2),'ks','MarkerSize',12); end legend(h,{'-1 (training)','+1 (training)','Support Vectors', ... '-1 (classified)','+1 (classified)', ... 'Correctly Classified','Misclassified'}, ... 'Location','Southeast'); hold off

### Plot Posterior Probability Regions for SVM Classification Models

This example shows how to predict posterior probabilities of SVM models over a grid of observations, and then plot the posterior probabilities over the grid. Plotting posterior probabilities exposes decision boundaries.

Load Fisher's iris data set. Train the classifier using the petal lengths and widths, and remove the virginica species from the data.

load fisheriris classKeep = ~strcmp(species,'virginica'); X = meas(classKeep,3:4); y = species(classKeep);

Train an SVM classifier using the data. It is good practice to specify the order of the classes.

SVMModel = fitcsvm(X,y,'ClassNames',{'setosa','versicolor'});

Estimate the optimal score transformation function.

```
rng(1); % For reproducibility
[SVMModel,ScoreParameters] = fitPosterior(SVMModel);
```

Warning: Classes are perfectly separated. The optimal score-to-posterior transformation is a step function.

ScoreParameters

`ScoreParameters = `*struct with fields:*
Type: 'step'
LowerBound: -0.8431
UpperBound: 0.6897
PositiveClassProbability: 0.5000

The optimal score transformation function is the step function because the classes are separable. The fields `LowerBound`

and `UpperBound`

of `ScoreParameters`

indicate the lower and upper end points of the interval of scores corresponding to observations within the class-separating hyperplanes (the margin). No training observation falls within the margin. If a new score is in the interval, then the software assigns the corresponding observation a positive class posterior probability, i.e., the value in the `PositiveClassProbability`

field of `ScoreParameters`

.

Define a grid of values in the observed predictor space. Predict the posterior probabilities for each instance in the grid.

xMax = max(X); xMin = min(X); d = 0.01; [x1Grid,x2Grid] = meshgrid(xMin(1):d:xMax(1),xMin(2):d:xMax(2)); [~,PosteriorRegion] = predict(SVMModel,[x1Grid(:),x2Grid(:)]);

Plot the positive class posterior probability region and the training data.

figure; contourf(x1Grid,x2Grid,... reshape(PosteriorRegion(:,2),size(x1Grid,1),size(x1Grid,2))); h = colorbar; h.Label.String = 'P({\it{versicolor}})'; h.YLabel.FontSize = 16; caxis([0 1]); colormap jet; hold on gscatter(X(:,1),X(:,2),y,'mc','.x',[15,10]); sv = X(SVMModel.IsSupportVector,:); plot(sv(:,1),sv(:,2),'yo','MarkerSize',15,'LineWidth',2); axis tight hold off

In two-class learning, if the classes are separable, then there are three regions: one where observations have positive class posterior probability `0`

, one where it is `1`

, and the other where it is the positive class prior probability.

### Analyze Images Using Linear Support Vector Machines

This example shows how to determine which quadrant of an image a shape occupies by training an error-correcting output codes (ECOC) model comprised of linear SVM binary learners. This example also illustrates the disk-space consumption of ECOC models that store support vectors, their labels, and the estimated $$\alpha $$ coefficients.

**Create the Data Set**

Randomly place a circle with radius five in a 50-by-50 image. Make 5000 images. Create a label for each image indicating the quadrant that the circle occupies. Quadrant 1 is in the upper right, quadrant 2 is in the upper left, quadrant 3 is in the lower left, and quadrant 4 is in the lower right. The predictors are the intensities of each pixel.

d = 50; % Height and width of the images in pixels n = 5e4; % Sample size X = zeros(n,d^2); % Predictor matrix preallocation Y = zeros(n,1); % Label preallocation theta = 0:(1/d):(2*pi); r = 5; % Circle radius rng(1); % For reproducibility for j = 1:n figmat = zeros(d); % Empty image c = datasample((r + 1):(d - r - 1),2); % Random circle center x = r*cos(theta) + c(1); % Make the circle y = r*sin(theta) + c(2); idx = sub2ind([d d],round(y),round(x)); % Convert to linear indexing figmat(idx) = 1; % Draw the circle X(j,:) = figmat(:); % Store the data Y(j) = (c(2) >= floor(d/2)) + 2*(c(2) < floor(d/2)) + ... (c(1) < floor(d/2)) + ... 2*((c(1) >= floor(d/2)) & (c(2) < floor(d/2))); % Determine the quadrant end

Plot an observation.

figure imagesc(figmat) h = gca; h.YDir = 'normal'; title(sprintf('Quadrant %d',Y(end)))

**Train the ECOC Model**

Use a 25% holdout sample and specify the training and holdout sample indices.

p = 0.25; CVP = cvpartition(Y,'Holdout',p); % Cross-validation data partition isIdx = training(CVP); % Training sample indices oosIdx = test(CVP); % Test sample indices

Create an SVM template that specifies storing the support vectors of the binary learners. Pass it and the training data to `fitcecoc`

to train the model. Determine the training sample classification error.

t = templateSVM('SaveSupportVectors',true); MdlSV = fitcecoc(X(isIdx,:),Y(isIdx),'Learners',t); isLoss = resubLoss(MdlSV)

isLoss = 0

`MdlSV`

is a trained `ClassificationECOC`

multiclass model. It stores the training data and the support vectors of each binary learner. For large data sets, such as those in image analysis, the model can consume a lot of memory.

Determine the amount of disk space that the ECOC model consumes.

```
infoMdlSV = whos('MdlSV');
mbMdlSV = infoMdlSV.bytes/1.049e6
```

mbMdlSV = 763.6150

The model consumes 763.6 MB.

**Improve Model Efficiency**

You can assess out-of-sample performance. You can also assess whether the model has been overfit with a compacted model that does not contain the support vectors, their related parameters, and the training data.

Discard the support vectors and related parameters from the trained ECOC model. Then, discard the training data from the resulting model by using `compact`

.

Mdl = discardSupportVectors(MdlSV); CMdl = compact(Mdl); info = whos('Mdl','CMdl'); [bytesCMdl,bytesMdl] = info.bytes; memReduction = 1 - [bytesMdl bytesCMdl]/infoMdlSV.bytes

`memReduction = `*1×2*
0.0626 0.9996

In this case, discarding the support vectors reduces the memory consumption by about 6%. Compacting and discarding support vectors reduces the size by about 99.96%.

An alternative way to manage support vectors is to reduce their numbers during training by specifying a larger box constraint, such as 100. Though SVM models that use fewer support vectors are more desirable and consume less memory, increasing the value of the box constraint tends to increase the training time.

Remove `MdlSV`

and `Mdl`

from the workspace.

clear Mdl MdlSV

**Assess Holdout Sample Performance**

Calculate the classification error of the holdout sample. Plot a sample of the holdout sample predictions.

oosLoss = loss(CMdl,X(oosIdx,:),Y(oosIdx))

oosLoss = 0

yHat = predict(CMdl,X(oosIdx,:)); nVec = 1:size(X,1); oosIdx = nVec(oosIdx); figure; for j = 1:9 subplot(3,3,j) imagesc(reshape(X(oosIdx(j),:),[d d])) h = gca; h.YDir = 'normal'; title(sprintf('Quadrant: %d',yHat(j))) end text(-1.33*d,4.5*d + 1,'Predictions','FontSize',17)

The model does not misclassify any holdout sample observations.

## See Also

`fitcsvm`

| `bayesopt`

| `kfoldLoss`

## Related Topics

- Train Support Vector Machines Using Classification Learner App
- Optimize Cross-Validated Classifier Using bayesopt

## References

[1] Hastie, T., R. Tibshirani, and J. Friedman. *The Elements of Statistical Learning*, second edition. New York: Springer, 2008.

[2] Christianini, N., and J. Shawe-Taylor. *An Introduction to Support Vector Machines and Other Kernel-Based Learning Methods*. Cambridge, UK: Cambridge University Press, 2000.

[3] Fan, R.-E., P.-H. Chen, and C.-J. Lin. “Working set selection using second order information for training support vector machines.”
*Journal of Machine Learning Research*, Vol 6, 2005, pp. 1889–1918.

[4] Kecman V., T. -M. Huang, and M. Vogt. “Iterative Single Data Algorithm for Training Kernel Machines from Huge Data Sets: Theory and Performance.” In *Support Vector Machines: Theory and Applications*. Edited by Lipo Wang, 255–274. Berlin: Springer-Verlag, 2005.