For Loop Problem error

3 views (last 30 days)
shalaw faraj
shalaw faraj on 15 Jul 2019
Commented: shalaw faraj on 15 Jul 2019
img=imread('C:\Users\Shalaw\Downloads\gray.jpeg');
[n,m]=size(img);
part1=img(1:n/2,1:m/2);
part2=img(1:n/2,(m/2)+1:end);
part3=img(n/2+1:end,1:m/2);
part4=img(n/2+1:end,m/2+1:end);
for i=1:4
subplot(2,2,i);
imshow(part1); -----> I want to change 1 to i, but i cant please help.
end
  1 Comment
Stephen23
Stephen23 on 15 Jul 2019
Edited: Stephen23 on 15 Jul 2019
Simply use a cell array with indexing:
Putting numbers into variable names is a sign that you are doing something wrong. In most cases using indexing is simpler, neater, and much more efficient.

Sign in to comment.

Accepted Answer

Adam
Adam on 15 Jul 2019
img=imread('C:\Users\Shalaw\Downloads\gray.jpeg');
[n,m]=size(img);
part{1}=img(1:n/2,1:m/2);
part{2}=img(1:n/2,(m/2)+1:end);
part{3}=img(n/2+1:end,1:m/2);
part{4}=img(n/2+1:end,m/2+1:end);
for i=1:4
subplot(2,2,i);
imshow(part{i});
end

More Answers (1)

Andrei Bobrov
Andrei Bobrov on 15 Jul 2019
img=imread('C:\Users\Shalaw\Downloads\gray.jpeg');
[n,m]=size(img);
imgs = mat2cell(img,[n,n]/2,[m,m]/2)';
for ii = 1:4
subplot(2,2,ii);
imshow(imgs{ii});
end
  3 Comments
Andrei Bobrov
Andrei Bobrov on 15 Jul 2019
k = 4;
[n,m]=size(img);
imgs = mat2cell(img, n/k*ones(1,k), m/k*ones(1,k))';
for ii = 1:k^2
subplot(k,k,ii);
imshow(imgs{ii});
end
shalaw faraj
shalaw faraj on 15 Jul 2019
I am very sorry, but I want to find (mean, max, min, std, entropy) for each block and using for but it is not working please help. thanks again.
img=imread('C:\Users\Shalaw\Downloads\gray.jpeg');
[n,m]=size(img);
part{1}=img(1:n/2,1:m/2);
part{2}=img(1:n/2,(m/2)+1:end);
part{3}=img(n/2+1:end,1:m/2);
part{4}=img(n/2+1:end,m/2+1:end);
for i=1:4
subplot(2,2,i);
imshow(part{i});
Xmean{i}=mean(part{i});
Xmax{i}=max(part{i});
Xmin{i}=min(part{i});
Xstd{i}=std(part{i});
Xentropy{i}=entropy(part{i});
end

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!