How can I download matlab R2016a?

As above

[Ellis Chika Onwordi]

Thanks for the answers and comments.

The link below offers downloads on previous versions going back to 2015b:

https://uk.mathworks.com/products/new_products/previous_release_overview.html

I have now downloaded it.

Answer 1

[Adam]

Click on your symbol in the top-right of this page, next to the telephone icon and click on 'My Account'. In your licencse list you should have a down arrow button for downloading. When you click this you get options for all the versions your license is valid for.

[Ellis Chika Onwordi]

Thanks. My licences don't cover that version it seems. When I look to buy it, I'm only offered R2019a (latest release). Am I missing an archive of previous versions going back to R2016a?

[Steven Lord]

Is there a particular reason you specifically need release R2016a? [If you were on a 32-bit OS, I could see you needing release R2015b as that was the last release supported on a 32-bit OS.] What's special about R2016a for your purposes?

[Adam]

I don't know honestly what a new license covers for backward usage. You'd be best asking Mathworks for that. My license has had continuous maintenance since around 2006 so I have access to a lot of previous versions (all the way back to R11.1, whatever that is!), but I only ever use the latest myself.

[Phetdanai]

Oh crap! It's gone.

[Walter Roberson]

@Adam

New licenses include provision to use all previous MATLAB versions.

However, institutions (workplaces, universities) can potentially turn off downloading of MATLAB, so if you buy a license for an institution or use a license for an institution, you might have difficulty accessing previous releases.

Answer 2

[Walter Roberson]

https://www.mathworks.com/downloads/web_downloads/download_release?release=R2016a

... provided that you are licensed for R2016a or later.

There are no trial licenses available for R2016a now, and R2016a is not free.

Answer 3

[fatima]

n=-10:10;

stem(n,n>=0);

title('unit step');

[Walter Roberson]

Could you please comment your solution? I do not understand how your code acts to download R2016a.