Mean of a Matrix
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Hi,
I have a 51x51 2D matrix that I need to take a mean off, but it has to give me back a 51x51 2D matrix as an output.
Please see the sample code below:
rand_image_stim = rand(10000,51,51);
kk = 1:length(rand_image_stim);
firing_rate_kk(kk) = 0;
gab_filt = z_cos.*z_gauss;
lp(kk) = 0;
for kk = 1:length(rand_image_stim)
output_kk = squeeze(rand_image_stim(kk,:,:)).*gab_filt;
firing_rate_kk(kk) = sum(output_kk,'all');
jk = squeeze(rand_image_stim(kk,:,:))*firing_rate_kk(kk);
lp = mean(jk,2); %this is where I need help
end
8 Comments
Rik
on 13 Nov 2019
So you need the mean, but you don't want to change the number of elements. How do you want to solve that? Do you want the mean to be repeated?
BBB
on 13 Nov 2019
Your code appears to be set up to expect a scalar value as the mean rather than a 51x51 output since you declare lp as a vector (incidentally, using length is not a good idea here, use size(..., 1 ) instead).
You need to give a clearer indication of what it is you wantm because you talk about a 2d matrix, but have a 3d array initially, which you loop around to have a succession of 2d matrices. You then keep overwriting the result from these in lp, which presumably should instead be
lp(kk) = ...
Unless you want to do a moving mean over a window I don't understand how you expect the mean of some number of values to return a result of the same size.
Steven Lord
on 13 Nov 2019
Let's take a simpler and smaller example.
A = reshape(1:75, [5 5 3]);
jk = squeeze(A(1, :, :));
Now, for this jk (which is 5-by-3) what exactly do you want the value of lp to be when you take its mean? Show us numbers and explain how you calculated those numbers from this jk matrix. That may help us understand what you want to do in your larger problem with a random rand_image_sim array.
BBB
on 13 Nov 2019
Sounds like it means average over the 10,000 images?
Which would just be a
squeeze( mean( ... ) )
operation on your full set 3d set of results, i.e. the mean along dimension 1, your 10,000, leaving you with a 51x51 end result.
BBB
on 13 Nov 2019
Adam
on 13 Nov 2019
I don't really have the time to look in depth at the code and give a full syntactically correct answer, but from what I can see you just want to store jk in the loop as e.g.
jk( kk, :, : ) = squeeze(rand_image_stim(kk,:,:))*firing_rate_kk(kk);
and remove the last line from the loop, then after the end of the for loop simply:
result = mean( jk );
should give what you want.
Answers (1)
your for loop is length(rand_image_stim). So your mean value calculated 10000 times. You should store it and later get the mean all.
Try this:
rand_image_stim = rand(10000,51,51);
kk = 1:length(rand_image_stim);
firing_rate_kk(kk) = 0;
gab_filt = z_cos.*z_gauss;
lp(kk,51) = 0; % 10000 x 51 matrix
for kk = 1:length(rand_image_stim)
output_kk = squeeze(rand_image_stim(kk,:,:)).*gab_filt;
firing_rate_kk(kk) = sum(output_kk,'all');
jk = squeeze(rand_image_stim(kk,:,:))*firing_rate_kk(kk);
lp(kk,:) = mean(jk,2); %this is where I need help
end
your_mean_value = mean(lp,'all');
3 Comments
BBB
on 13 Nov 2019
I have made a small edit to my answer please check again. You will have 10000 mean values for each loop. It is not possible to get 51x51 mean values. Or did I misunderstand? if you want to get 51x51 mean values in the end you should have kk = 51 but it is 10000. Also in the beginning you initialize lp 1x10000 vector filled with zeros already.
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