How do i multiply 2 increasing variables

Hello everyone i was wondering if u could help me multiply these two increasing variables. They just do not multiply correctly
v0 = (10:1:20);
theta = (30:1:40);
v0_x = v0.*cosd(theta);
v0_y = v0.*sind(theta);

6 Comments

What do you think is incorrect?
It may not be what you were trying to compute, but the result of the two expressions is certainly what would be expected by MATLAB syntax.
What does "do not multiply correctly" mean in this context?
  • Do you receive warning and/or error messages? If so the full and exact text of those messages (all the text displayed in orange and/or red in the Command Window) may be useful in determining what's going on and how to avoid the warning and/or error.
  • Does it do something different than what you expected? If so, what did it do and what did you expect it to do?
  • Did MATLAB crash? If so please send the crash log file (with a description of what you were running or doing in MATLAB when the crash occured) to Technical Support using the telephone icon in the upper-right corner of this page so we can investigate.
I think is correct.
i was expecting the code to create the solutions like this,
10*cosd(30) 11*cosd(30) 12*cosd(30) 13*cosd(30) ....
10*cosd(31) 11*cosd(31) 12*cosd(31) ......
10*cosd(32) 11*cosd(32) ......
10*cosd(33) .......
To get this you need to use symbolic tool box.
for v0 = 10:1:20;
for theta = 30:1:40;
v0_x = v0.*cosd(theta)
v0_y = v0.*sind(theta)
end
end
Do you need this?

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 Accepted Answer

Shae Morgan
Shae Morgan on 14 Aug 2020
Edited: Shae Morgan on 14 Aug 2020
Is this more what you were looking for?
v0 = (10:1:20);
theta = (30:1:40);
for i= 1:length(v0)
for j = 1:length(theta)
v0_x(i,j)=v0(i)*cosd(theta(j));
v0_y(i,j)=v0(i)*sind(theta(j));
end
end
v0_x
v0_y

4 Comments

yes this is correct, thank you
If you wanted that..simply use:
v0 = (10:1:20);
theta = (30:1:40);
[v0,theta] = meshgrid(v0,theta) ;
v0_x = v0.*cosd(theta);
v0_y = v0.*sind(theta);
i am not familiar with meshgrid
meshgrid() is another great solution here
x=[1 2 3]; %x array
y=[3 2 1]; %y array
[X,Y]=meshgrid(x,y)
%X is a length(y) long set rows of x
%Y is a length(x) long set of columns of y
using these matrices with the point multiplication will give the same outcome. The for-loops feel more intuitive and are visually understandable as you read through the code, but meshgrid requires fewer lines and a little more understanding of what it's doing.
In the end it's preference. I prefer code readability (or familiarizing yourself with new functions so you can improve readability!)

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More Answers (1)

Bruno Luong
Bruno Luong on 14 Aug 2020
Edited: Bruno Luong on 14 Aug 2020
v0 = (10:1:20);
theta = (30:1:40);
v0_x = v0.*cosd(theta.'); % horizontal .* vertical vectors
v0_y = v0.*sind(theta.');

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