function B = gameOfLife(A)
B=A;
C=[A,A,A;A,A,A;A,A,A];
for i=5:8
for j=5:8
cnt=0;
for m=i-1:i+1
for n=j-1:j+1
if m==i&&n==j
cnt=cnt;
else
if C(m,n)==1
cnt=cnt+1;
end
end
end
end
if C(i,j)==1 %该细胞现在存活
if cnt>3||cnt<2
B(i-4,j-4)=0;
end
else %该细胞现在死亡
if cnt==3
B(i-4,j-4)=1;
end
end
end
end
end

Is there something wrong with the test suite?

function B = life(A)
B = A;
end

produces "Error using life Too many output arguments."

This solution is for only a 4x4 A. See Solution 598430 for general solution.

This is the solution for A of any size.

Ties the current leader in size, but works on all board sizes.

This stops working if the input is not 4x4.

Nice way of expanding A for circular convolution

Humph! Solution 2234 uses imfilter, but this fails with imfilter not found!

Nice - but only works for 4x4 boards.

Puzzling - solution 2231 uses imfilter but this solution fails because padarray isn't available. Both are in the IPT.

Nice usage of a simpler matrix for convolution (ones(3)) and readjustment of the logical conditions.

Good job!

I was looking for a command to do a circular convolution, but couldn't figure it out. This is useful to learn and, I guess, the whole point of Cody

However, learning is severely hindered by not being able to view solutions of smaller size. At least, as far as i know, this is not possible.

_All_ solutions in this Problem will become viewable after you solve _another_ Problem in the same category (which here is "Cody Challenge").