Create n x 2n "mirror" matrix of this type:
For n = 2
m = [ 1 2 2 1
1 2 2 1 ]
For n = 3
m = [ 1 2 3 3 2 1
1 2 3 3 2 1
1 2 3 3 2 1 ]
This problem was fun. I was able to find a better way to solve beat my own solution. Not the best way though. But lot better.
Given an unsigned integer x, find the largest y by rearranging the bits in x
Reverse the Words (not letters) of a String
Output any real number that is neither positive nor negative
03 - Matrix Variables 5
Is this triangle right-angled?
Sum of series VI
Sum of series IV
Sum of series III
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